Windows 7 Question

[Kevin Simonson]

This is obviously not the forum for this question, since this forum is about how Linux or UNIX relate to Java, but I don't see a forum dedicated to Windows 7. Does anyone know of a discussion forum for Windows 7 machines?

My question in particular has to do with three batch files, "Both.bat" that consists of:
@echo off First Second
"First.bat" that consists of:
echo First
and "Second.bat" that consists of:
echo Second
When I execute "Both.bat", I find that it executes "First.bat" but never returns to execute "Second.bat". Does anybody know a way to get around that, to get a batch file to execute another batch file but then return to the first batch file when the second one finishes?

[Tim Cooke]

You're right, we don't have a dedicated forum for Windows 7. We have Linux/UNIX because the majority of Java Enterprise applications are deployed on some flavour of UNIX, such as RedHat and Solaris. We don't get enough Windows specific questions to warrant its own fourm, so the General Computing forum will suffice. I've moved your questions over there so you're more likely to get a reply.

[fred rosenberger]

if you reverse the two in both.bat, what does it print? what if you just have second in it?

[Joe Ess]

Kevin Simonson wrote:When I execute "Both.bat", I find that it executes "First.bat" but never returns to execute "Second.bat".

This behavior is an artifact from the old DOS days. When one batch file invokes another, control is given to the second file. It does not return. If you want to return to the first batch file, you need to use the CALL command.

[Kevin Simonson]

fred rosenberger wrote:if you reverse the two in both.bat, what does it print? what if you just have second in it?

If I reverse the order, it just prints "Second"; if I just have Second in it, it still just prints "Second".

[Kevin Simonson]

Joe Ess wrote:

Kevin Simonson wrote:When I execute "Both.bat", I find that it executes "First.bat" but never returns to execute "Second.bat".

This behavior is an artifact from the old DOS days. When one batch file invokes another, control is given to the second file. It does not return. If you want to return to the first batch file, you need to use the CALL command.

This fixed my problem. Thanks!