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Exception Handling

 
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Posts: 143
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public float parseFloat(String s)
{
float f = 0.0f;
try
{
f = Float.valueOf(s).floatValue();
return f ;
}
catch(NumberFormatException nfe)
{
System.out.println("Invalid input " + s);
f = Float.NaN ;
return f;
}
finally { System.out.println("finally"); }
return f ;
}
Why this code from JQ+ does not compile?
 
Author & Gold Digger
Posts: 7617
6
IntelliJ IDE Java
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What happens if you compile the code???

The return statement after the finally block is not reachable because there already is a return statement in the try and another one in the catch block. So whatever happens, one of those two will be executed and the one outside is unreachable.
 
Arun Pai
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Thanks Val. Now I am clear.
 
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