Dear Mr. Barry Gaunt,
What i think each will have lock of a new object which is created,that means every
thread has a lock for itself,that means each can run the method run() even simultaneously and it might be that the
numbers which are printed can be missed or even repeated. Please Confirm Me by Posting,
Thanks,
With Regds,
Anand
Thanks and Regards, Anand
SCJP 5.0 310-055 73%, SCWCD 1.4 310-081 78%, IBM DB2 9 Fundamentals 000-730 62%