Originally posted by archana prabhu:
b1=true,b2=true,b3=false
b3&=b1|b2->this evaluates to false
b3=b3&b1|b2->this evaluates to true
why does it give different result?
| has a higher precedence than &=
so b3 &= b1|b2 is the same as b3 &= (b1|b2) which is b3 &= true which is false since b3 is false.
& has a higher precedence than |
so b3 = b3 & b1 | b2 is the same as b3 = (b3 & b1) | b2 = false | true = true.