Constructor Doubt

[Deepak Bobal]

class top
{
public top() //line 3
{
System.out.println("top");
} //line 6
public top(String s)
{
System.out.println("BB");
}
}
public class bottom2 extends top
{
public bottom2(String s)
{
System.out.println("DD");
}
public static void main(String[] arg)
{
new bottom2("CC");
System.out.println("Invoked ");
}
}


In the above code sample
Output is >
top
DD
Invoked
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Why "BB" is not getting printed???
***************************************
If i am right the program flow is
1:new button2("CC");
2:calls it's super class constructor > public top(String s)
3:then it class it's super class constructor......keeps on to Object class
4:then starts initialization
This way it happens.If my floe to understand this is wrong, please suggest me.
**********************************
My second question is if i comment from line 3 to line 6 ,it shows compilation error.According to me it shouldn't .As Class top and bottom2 have same argument constructor.


thanks
Deepak

[Henry Wong]

2:calls it's super class constructor > public top(String s)

Why do you believe that a constructor will call the super constructor with the same signature? If this was true, then wouldn't the Object class need a constructor for every possible combination of constructors?

Henry

[Ajay Singh]

your second point is wrong,super makes an implicit call to the no argument constructor of the parent class instead of the argument constructor.If you comment those lines super cant find a no argument constructor of the parent class and hence the error.