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Question from examlab practice test 3

 
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This is from practice exam 3 of examlab



here answer is D. will compile succesfully if volatile keyword is removed
I. prints 000000

Here i could not understand if the current code gives compiler error then how come it is printing 000000
even if we remove the voatile keyword then i think it should give output as 221210. please clear my doubt.

thanks,
geeta vemula
 
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I will give you a hint.


Concentrate on this line, and do your best to try why? And tell me the answer also.
 
geeta vemula
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oh i was so stupid...

First all the instantiation done where x will become 0 in tht line which is same since it is class variable. so printing 000000.

Thanks,
for clearing my doubt..
 
Punit Singh
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Excellent
 
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geeta vemula wrote:oh i was so stupid...

First all the instantiation done where x will become 0 in tht line which is same since it is class variable. so printing 000000.

Thanks,
for clearing my doubt..



Thanks for explaination guys.
That line tricked me too.
I also thought the answer should be '000' becuase the print statement is executed three times.
But I manually went through the code step by step and figured out that the static String variable 's' keeps the previous '0's and thus prints out 6-'0's.
Very tricky!
-Thank You
 
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