File path issues while reading an xsl file in java

[chandana lakku]

Hi,

I want to read an xsl file from a java class(which is located in a package com.a.b.c)

xsl file and the java class resides in the same package.(com.a.b.c)

The possible ways that i tried:

String xsltFile = "test.xsl";
String xsltFile = new File("test.xsl").toURL().toExternalForm( );
String xsltFile = new File("test.xsl").getAbsolutePath();
String xsltFile = new File("test.xsl").getPath( );
String xsltFile = new File("test.xsl").getPath( );
String xsltFile = "com/a/b/.../test.xsl"

All the above methods returns file path (where the application is deployed) but the actual xsl file doesn't exist there.

How should I read this "xsl file" from my java class which is located in the same path?

Could some one help me out on it?

Thanks & Regards,
Chandana.

[Rob Spoor]

Stop using File and String, and start using Class.getResource and Class.getResourceAsStream instead.

[shirish katti]

Hi chandana Try out with this..


import java.io.BufferedReader;
import java.io.DataInputStream;
import java.io.FileInputStream;
import java.io.InputStreamReader;

public class FilePath {
public static void main(String[] args) {
try{
FileInputStream fs=new FileInputStream("Path to your Xsl file");
DataInputStream in=new DataInputStream(fs);
BufferedReader br=new BufferedReader(new InputStreamReader(in));
String strLine;
while((strLine=br.readLine())!=null){
System.out.println(strLine);
}
in.close();
}catch(Exception e){
System.out.println("Error:"+e.getMessage());
}
}
}

I am sure it will work as it worked for me.. Enjoyyyyyyyy..........

[Rob Spoor]

Please both use code tags.

Shirish, that will only work when the file is always located in the same folder. You can't assume that the application has been started in its root folder, or the folder where the JAR file is located. Resources are always relative to a class or the entire class path, so those seem more appropriate.

[Campbell Ritchie]

And welcome to the Ranch

[shirish katti]

Shirish, that will only work when the file is always located in the same folder. You can't assume that the application has been started in its root folder, or the folder where the JAR file is located. Resources are always relative to a class or the entire class path, so those seem more appropriate.

Hi Rob,

Yes if the location of file changes, then we do have properties file were we can change the path of the file to be read..

If you do have any proper solution than this then please share it..

[Rob Spoor]

I already mentioned Class.getResourceAsStream. So instead of

FileInputStream fs=new FileInputStream("Path to your Xsl file");
DataInputStream in=new DataInputStream(fs);

you write

InputStream is = FilePath.class.getResourceAsStream("Path to your Xsl file relative to the class file");
DataInputStream in = new DataInputStream(is);

And if you call this in an instance method you can use getClass().getResourceAsStream(...).

[shirish katti]

Thanks Rob, i Got it..