how to add number of digit in array

[vineet walia]

please help me out

what i want is ...

1.user enter no of digit of tat number
2.thn use enter tat number

so i want to store tat number in array..
please help me out i try some code but unable to do

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

// addition of digits to array 

public class test {
public static void main(String str []) throws NumberFormatException, IOException
    {   
	      System.out.println("Enter no of digit of number");
	      BufferedReader b = new BufferedReader(new InputStreamReader(System.in));
	      int number= Integer.parseInt(b.readLine());
	          
	      int array_hold []= new int [number-1];
	      
	      System.out.println("Enter number");
		   BufferedReader c = new BufferedReader(new InputStreamReader(System.in));
		      int number_user= Integer.parseInt(c.readLine());
          // addition of digits of number in array 
	      
	      for(int i=0;i<number;i++)
	      {     int num1,num2;
	               num1=(int)Math.pow(10, number-(i+1));
                    num2=(int)Math.pow(10, number-(i+1)-1);
                    
                    int rl=(int)number_user%num1;
                    array_hold[i]=(int)rl%num2;
                    
	      }
	      
     	     for(int num:array_hold)
             System.out.println(num);
    }
}

>

[Tim McGuire]

the final time through the loop,

number-(i+1)-1 

always evaluates to zero

so num2 ends up being zero and this causes a division by zero error when you say

array_hold[i]=(int)rl%num2;

[vineet walia]

Tim McGuire wrote:the final time through the loop,

number-(i+1)-1 

always evaluates to zero

so num2 ends up being zero and this causes a division by zero error when you say

array_hold[i]=(int)rl%num2;

so how we can resolve this problem???

[Janeice DelVecchio]

You could loop one less time and handle outside the loop or set an if statement inside the loop to take care of the last entry.