i = i++; .....?

[Prashant Neginahal]

Hi All,
Look at the code below,
public static void main(String args[])
{
int i =0;
i = i++;
System.out.println(i);
}
It is printing 0 , but i was expecting 1.
Will anyone pls explain me..?
--------------
Prashant

[Chetan M]

Hi,
That is bcoz ... i++ means.. for the execution in current line the value of i will be still 0.But as control goes to next line., next time i is accessed for any operation, its value will be changed.. So it becomes 1. If instead of i++ if u use ++i .. in the execution of i = ++i , i value will be incremented n new value of i i.e 1 is assigned to i.So o/p 'll be 1.
Above stmt is justifed better with following code..
public static void main(String args[])
{
int i =0;
i = i++;
System.out.println(i);
i = ++i;
i = i++;
System.out.println(i);
}
Hope stmt is justified
###################################################
WISH U ALL HAPPY NEW YEAR 2003
HAKUNAMATATA !!!

[ January 01, 2003: Message edited by: Chetan Mishra ]
[ January 01, 2003: Message edited by: Chetan Mishra ]

[Peter Wu]

The i++ operand evaluates i to 1 but reutrn 0. Since the ++ operand takes precedence before the assignment, 0 assigns to variable i at last.
Hope this helps.

[Jessica Sant]

It's kinda like when you ket a cut on your elbow and you go up to your mom and say "Mom -- it hurts when I move like this..." and your mom says -- "So, don't move like that."
The moral of this story is: so don't do that in your code -- its confusing to read and just plain silly.

[Prashant Neginahal]

Thats rt Peter.But still i have doubt.....
1. int i=1,j=1;
2. i=j++;
3.
At line 2 , fallowing things will happen,
a) Coz of hiegher precedence of ++ ,it is applied to j variable. rt?
b)next, assignment takes place.
If this is the case,Is it that there are two copies of j.'i' is pointing to first copy and its assigned only after another copy of j gets incremented.

[Valentin Crettaz]

Maha's technique for solving ++ and -- related problems

[Aaron Anders]

how about this...

class A
{
    public static void main(String [] args)
    {
        int i=0;
        System.out.println( (i=i++)==(i=++i) || (i++)==(++i) );
        System.out.println( i );
    }
}

why does i become 3?
[ January 02, 2003: Message edited by: Aaron Anders ]

[Barry Gaunt]

After i=i++, i is 0.
After i=++i, i is 1.
Comparison is false so do bit after the ||
After i++, i is 2
After ++i, i is 3.
Second comparison is 1 == 3, which gives false