thanks. I really don't know physics or electronics very well. i just went to a physics web page and grabbed a formula that would (IMHO) help substantiate my point.
erroneous use of the term "hypothesize".
i did not say "it is in fact a simple linear graph". what i said was, using algebra, we can convert the 'complicated' equation into a 'simpler' one, with the same solution set (i.e. for every x in the the domain, i get the same y in the range). However, since my original equation does NOT allow for me to have an x value of 5, i can't use an x value of 5 in my 'simplified' version of the equation. it's simply not allowed.
now, if i were JUST graphing y = x+2, then there would be no hole. but i am not. i am graphing that more complicated equation. So i am bound by ITS domain. HOW i go about graphing that is irrelavent to the actual solution.
it simply has no size - as in it has a width of 0, and a height of 0
code:
x^2 - 3x -10
y = ----------------
x - 5
code:
void orangesPerEmployee(int oranges, int employees){
return oranges/employees;
}
if orangesPerEmployees = 0, code will likely assume:
"Oh, there weren't any oranges for the employees! We must need more oranges"
when in fact there was 6.022 x 10^23 oranges, just no employees.
Or we can listen to them to get a better understanding what they mean. Until then, I'll be asleep in the corner.
For instance: If you divide up a pie into 9 pieces, you could say each piece is "1/9" of the original. Or it might be "0.111(1)" of the originial. Or it might be "0.1 (base 9)" of the original. The fact that in base 10 the piece of pie has a repeating representation while in base 9 it has a terminating representation doesn't change the piece itself; it's still just one ninth of the pie.