Is this the correct way to compile code that uses classes in another jar file

[Tony Evans]

<property name="source" value="."/>
<property name="lib" value="${source}/lib"/>
<property name="build" value="${source}/build"/>
<property name="config" value="${source}/config"/>
<property name="client" value="${source}/client"/>

<target name="compile">
<mkdir dir="${build}"/>
<mkdir dir="${client}"/>
<javac srcdir="${source}" destdir="${build}" includes="*.java">
<classpath>
<fileset dir="${lib}">
<include name="*.jar"/>
</fileset>
</classpath>
</javac>
</target>

I have my jar under the ./lib directory and
<echo>
${lib}
</echo>

outputs ./lib

Thanks for any help

Tony

[Tim Holloway]

Here's an excerpt from a real-world project:

<path id="project.class.path">
 
<pathelement path="${java.class.path}" />
 
<pathelement path="${build.spi.classes.dir}" />
 
<fileset dir="lib">
 
<include name="*.jar" />
 
</fileset>
 
</path>
 
<target name="spi-compile" depends="init" description="Compiles the SPI">
 
<mkdir dir="${build.spi.classes.dir}" />
 
<javac srcdir="${java.spi.src.dir}" destdir="${build.spi.classes.dir}"
 
            source="${java.source.version}"
 
            target="${java.target.version}"      
 
            debug="true" debuglevel="source,lines,vars"
 
            optimize="${build.optimize}" deprecation="true">
 
<classpath refid="project.class.path" />
 
</javac>
 
</target>

I hope it's not too confusing - I ripped it out of a very large project, so there may be some strange references left in there.