Because you have created a closure with your inline function, it will have access to all the variables in scope for the block in which it is declared including myAjax (but not the this pointer). [ July 12, 2006: Message edited by: Bear Bibeault ]
Originally posted by Bear Bibeault: Because you have created a closure with your inline function, it will have access to all the variables in scope for the block in which it is declared including myAjax (but not the this pointer).
[ July 12, 2006: Message edited by: Bear Bibeault ]