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XML data not displaying with XSL

 
Chris Behr
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Posts: 17
posted 23 years ago
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I have just started learning XML so bear with me. I have a xml document that I created and want to use a stylesheet to display it in html but it doesn't seem to be working. Here is the xml file:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet href="XSL\myXSL.xsl" type="text/xsl"?>
<GstBk:Book xmlns:GstBk="http://www.testurl.com">
<GstBk:Guest>
<GstBk:Address>
<GstBk:Name>John Doe</GstBk:Name><GstBk:From>Anywhere USA</GstBk:From>
</GstBk:Address>
</GstBk:Guest>
</GstBk:Book>
And here is the xsl document:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:GstBk="http://www.testurl.com"
version="1.0"
>
<xsl:template match="GstBk:Book">
<html>
<head>
<title>Guest Book</title>
</head>
<body>
<xsl:apply-templates />
</body>
</html>
</xsl:template>
<xsl:template match="GstBk:Guest">
Name = <xsl:value-of select="GstBk:Name" />
</xsl:template>
</xsl:stylesheet>
But the only data I get on the browser is:
Name =
Can anyone see something wrong with my files? I have downloaded examples from the net and they seem to work. I even compared them to my files and can't see anything obviously different. Any ideas?
Thanks
 
Sumedh
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Posts: 3
posted 23 years ago
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Chris,
You need to have "GstBk:Address/GstBk:Name" instead of "GstBk:Name".
<xsl:template match="GstBk:Guest">
Name = <xsl:value-of select="GstBk:Address/GstBk:Name" />
</xsl:template>
-Sumedh
 
Chris Behr
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Posts: 17
posted 23 years ago
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It still doesn't seem to be working. I changed my XSL to:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:GstBk="http://www.testurl.com"
version="1.0"
>
<xsl:template match="GstBk:Book">
<html>
<head>
<title>Guest Book</title>
</head>
<body>
<xsl:apply-templates />
</body>
</html>
</xsl:template>
<xsl:template match="GstBk:Guest">
Full Name = <xsl:value-of select="GstBk:Address/GstBk:Name" />
</xsl:template>

</xsl:stylesheet>
And all I get is:
Full Name =
Do you have any other ideas on what I might be doing wrong?
Thanks
 
Kris Decker
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Posts: 38
posted 23 years ago
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I have found varying behavior with XSL depending on whether I use XML Spy or IE.
Also, the Namespace will have an impact
[This message has been edited by Kris Decker (edited August 29, 2001).]
 
Anonymous
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Posts: 18944
posted 23 years ago
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Hi Chris,
What transformation engine are you using? For me, the fixed example works fine with Xalan2-Java and with Microsoft IE5.5.
As an alternative to Sumedh's fix, you can also use:
<xsl:value-of select=".//GstBk:Name" />
This selects all the descending nodes (.//GstBk:Name is a shortcut for self::node()/descendant-or-self::node()/GstBk:Name)
Cheers,
Beno�t
 
Chris Behr
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Posts: 17
posted 23 years ago
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I am running thru a service provider but as far as I can tell they are using apache cocoon 2 if that means anything to you.
 
Darryl Andrew
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Posts: 12
posted 23 years ago
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Originally posted by Beno�t d'Oncieu:
Hi Chris,
What transformation engine are you using? For me, the fixed example works fine with Xalan2-Java and with Microsoft IE5.5.
As an alternative to Sumedh's fix, you can also use:
<xsl:value-of select=".//GstBk:Name" />
This selects all the descending nodes (.//GstBk:Name is a shortcut for self::node()/descendant-or-self::node()/GstBk:Name)
Cheers,
Beno�t


Hi, since u r using xalan2, can u pls tell me what are the path to use? i include xalan2.jar, xerces.jar, xalanservlet.jar and servlet.jar in my path when running the servlet example provided in xml.apache.org using xalan2.jar. But i'm still experiencing java.lang.NoClassDefFoundError error
 
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