XSL Question

[Srini vempuluru]

Hi,
I have an xml in the following format.
<Employee>
<Name> Srini </Name>
<Address>
<State>VA</State>
</Address>
</Employee>

I wrote an xsl to retrieve the content of Address node
<xsl:template match="Employee">
<xsl:value-of select="Address"/>
</xsl:template>
The above lines are retrieving the value as "VA" instead of <State>VA</State>.
Please let me know is there any way to retrieve the child tags also.
Thanks in advance.
Srini

[Mapraputa Is]

You need to use
<xsl:copy-of select="Address"/>
instead of
<xsl:value-of select="Address"/>

[Jayadev Pulaparty]

A little correction -
<xsl:copy-of> copies everything in the tree of encompassed by the supplied node and hence <xsl:copy-of select="Address"/> will give the following output -
<Address>
<State>VA</State>
</Address>
But, if you just need <State>VA</State>, you need to modify ur xpath expression as
<xsl:copy-of select="Address/State"/>
The complete output by running the stuff thru an xslt_processor looks like below -
<?xml version="1.0" encoding="UTF-8"?>
<State>VA</State>
No idea as to how to get rid of the
PI <?xml version="1.0" encoding="UTF-8"?>
in the output ........