SAX Help

[Balaji Loganathan]

Hi,
I have a XML like this.

  <Root> 
   <data>
    <id>TP5</id>
    <service>hello world</service>
   </data>
   <data>
    <id>UT5</id>
    <service>javaranch</service>
   </data>
   .....
   .....
   <data>
    <id>LR33</id>
    <service>soap-uddi</service>
   </data>
  </Root>
  

With SAX I can able to find whether a given <id> exist or not,
like this,
public void startElement(String nsURI, String localName,
String qName, Attributes attrs)
throws SAXException{
if ( localName.equals("LocationCoded") ) codestatus = true;
}
public void characters(char[] ch, int start, int length)
throws SAXException {
if (codestatus){
String value = new String(ch, start, length);
if (value.equals("ADALV")) {
System.out.println("Found!.");
}
}
}
I'm fine with this.
Now my problem is
Printing the <service> value for a given valid <id>
That is if <id> TP5 is given then it should print "hello world".
if <id> UT5 is given then it should print "javaranch"
With DOM i can able to do this,but my xml file size is 3.46MB so i want to use SAX.
Please give me some coding tips on how to do this with SAX.
Regards
Bala

[Jayadev Pulaparty]

Balaji,
I feel that there will not be any straight-forward SAX solution for the problem you put here. The only possible way out i see here is come out with an algorithm and implement it. I'm sure you are aware of this Please donot get angry with me
Have a good day.

[Balaji Loganathan]

[Dan Drillich]

If you can count on the fact that the service element always follows the id element you can do the following -
Create two instance variables -

private boolean isServiceElement = false;
private boolean found = false;  

In the startElement method please place (raw is the third parameter) -

if (raw.equals("service")) {
 isServiceElement = true;
} else {
 isServiceElement = false;
}
  

In the characters method please add -

String value = new String(ch, start, length);
if (found && isServiceElement) {
System.out.println(value);
found = false;
}
if (value.equals("LR33")) {
found=true;
}  

That should do it.
Cheers,
Dan

[Jayadev Pulaparty]

Dan's suggestion sounds good for me.
BTW, these face icons are really funny I like them a lot

[Balaji Loganathan]

Originally posted by Dan Drillich:

Dan, you gave me a beautiful solution.Shit me, i'm not even thinking about this logic.But tried something different than this.
Thanks a lot Dan,its worked perfectly.
Hi jaya,
this is for you
:roll:
Have a nice day.

[Dan Drillich]

Balaji,
You are welcome!
Dan