SaxParseException

[Dave Ehrlich]

I am calling a .NET web service from a Java client. I have been able to successfully send string data from the Java client to the .NET web service. When I try to extract the response, I get the following error:
"Content is not allowed in prolog".
The error is thrown from the following line of code:
xmlReader.parse( new InputSource(
new StringReader( soapMsg.getContent().toString() ) ) );
This seems to imply that there's something about the SOAP format being sent back that is a problem. My SOAP response is as follows:
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<DownloadTablesResponse xmlns="http://SLR.org/">
<DownloadTablesResult>Success</DownloadTablesResult>
</DownloadTablesResponse>
</soap:Body>
</soap:Envelope>
Any help would be appreciated.
Thanks,
Dave

[Ritu Kama]

Hi,
Can you post your client code to give some more idea of how you are recieving the response from .NET Web service.
Ritu

[Dave Ehrlich]

Here is the client clode that handles the response. The code is based on a How To article from MSDN at:
HOW TO: Integrate an Apache SOAP 2.2 Client with a .NET XML web service
It works well for trasmitting the data, but I can't read the string being sent back by the web service.

// Because the Body.unmarshall handler is static,
// you cannot replace the basic machinery easily.
// Instead, you must obtain and parse the 
// message on your own. 
soapMsg = message.receive();
XMLReader xr = XMLReaderFactory.createXMLReader(
"org.apache.xerces.parsers.SAXParser"); 
ClientHandler ch = new ClientHandler();
ch.setElementToSearchFor("DownloadTablesResult");
// Set the ContentHandler. 
xr.setContentHandler( ch ); 
// Parse the file. 
xr.parse( new InputSource( 
new StringReader( soapMsg.getContent().toString() ) ) );
// At this point, the result has been parsed and stored
// within the ClientHandler instance.
//retval = ch.getResult();
  

[Ritu Kama]

Is there a way you can dump the raw stream on the screen or file to see what's coming in exactly.
The code doesn't seem to have any error the way described in the URL document.

[Balaji Loganathan]

Originally posted by Dave Ehrlich:
I am calling a .NET web service from a Java client. Thanks,
Dave

Hi Dave,
Try to run the below java client code from ur machine which access a web service from ASP.NET and invoke an operation "ADD", I used WSDL2Java utility from apache axis to write this java client code,if that suits your case then u can give a try.BYW the below code is not a good pattern to write java client code.See wsdl2java pattern.

import org.apache.axis.client.Call;
import org.apache.axis.client.Service;
import org.apache.axis.encoding.XMLType;
import org.apache.axis.utils.Options;
import javax.xml.rpc.ParameterMode;
public class CalcClient_NET
{
   public static void main(String [] args) throws Exception {

       String endpoint = "http://samples.gotdotnet.com/quickstart/aspplus/samples/services/MathService/VB/MathService.asmx";
       Service  service = new Service();
       Call     call    = (Call) service.createCall();
       call.setTargetEndpointAddress( new java.net.URL(endpoint) );
       call.setOperationName(new javax.xml.namespace.QName("http://tempuri.org/", "Add"));
       call.addParameter(new javax.xml.namespace.QName("http://tempuri.org/", "A"), new javax.xml.namespace.QName("http://www.w3.org/2001/XMLSchema", "float"), float.class, javax.xml.rpc.ParameterMode.IN);
       call.addParameter(new javax.xml.namespace.QName("http://tempuri.org/", "B"), new javax.xml.namespace.QName("http://www.w3.org/2001/XMLSchema", "float"), float.class, javax.xml.rpc.ParameterMode.IN);
       call.setReturnType(new javax.xml.namespace.QName("http://www.w3.org/2001/XMLSchema", "float"), float.class);
   call.setSOAPActionURI("http://tempuri.org/Add");
   System.out.println("Got result : " + call.invoke(new Object[] {new Float(3.2), new Float(4.2)}));
   }
}

I guess the moderator will soon move this thread to web services

[Dave Ehrlich]

Rita,
The following commands:

String soapText = soapMsg.getContent().toString();
System.out.println(soapText);

produce the following result from the Windows command (DOS) window:
java.io.ByteArrayInputStream@66e815
I don't know if its a problem with how I'm trying to dump the input stream or something else. The strange thing is that TcpTunnelGui shows the SOAP response correctly.
Thanks,
Dave

[Anonymous]

Hi Dave,
This means that the soapMsg.getContent() returns an InputStream
Just read the contents of this input stream into a string. You can use the following method to do so:

public String readFully(InputStream is) throws IOException {
    BufferedReader br = null;
    StringWriter writer = new StringWriter();
    try {
        InputStreamReader in = new InputStreamReader(is);
        br = new BufferedReader(in);
        char c[] = new char[2048];
        int read = 0;
        while ((read = br.read(c)) != -1) {
            writer.write(c, 0, read);
        }
    } finally {
        if (null != br) {
            br.close();
        }
    }
    return writer.toString();
}

This just highlights one more time the risks of using the toString() method
[ November 19, 2002: Message edited by: Beno�t d'Oncieu ]

[Dave Ehrlich]

Solved!!!
Benoit,
Although I didn't need your code in the final result, it was crucial in making the breakthrough that determined the correct answer.
The original code below won't work because the parser wants a character string:

xr.parse( new InputSource( 
new StringReader( soapMsg.getContent().toString() ) ) );

However, this code works:

xr.parse( new InputSource(new  InputStreamReadersoapMsg.getInputStream()))); 

It seems that the parser want a character stream and not an input stream.
If there are any comments on this, or how it could be done better, please let me know.
Thanks,
Dave