SAXParser not Validating

[Joe Shy]

Hello,

I am assuming I am missing some sort of SAX Property, but I have an XML with a schema defined in an outside file. (so name.xml and name_schema.xsd). The issue is that the schema works fine in XMLSpy and Stylus Studio, but when I run the SAXParser, the document isn't validating 'correctly'(parses whether the data is valid or not) even when I use the method .setValidating(true) . My java code looks like the following. If you need something else, please let me know. The xml is just the root, child element with 3 children repeated.

SAXParserFactory factory = SAXParserFactory.newInstance();
        factory.setValidating(true);
        
        try {
            // Parse the input
            SAXParser saxParser = factory.newSAXParser();
            
            saxParser.parse( new File("dsn_names.xml"), handler);
        } catch (Throwable t) {
            t.printStackTrace();
        }

Thanks,
Joe

[Paul Clapham]

I haven't tried this myself, but this document appears to describe the process you need.

[Joe Shy]

I tried using that process from IBM and it didn't produce anything different. I made sure I matched the process and nothing. I even went and downloaded the latest jdk and jaxp. It isn't a huge issue, but the users that will possibly edit the xml file won't have a way to validate (or know how), that is why I was looking into this. If there is another solution, I would be open to exploring it.

Thanks for the help,
Joe

[Joe Shy]

I figured out how to Validate with Java 1.4.2 and SAX(2.0). I had to download the new SAX jars from sun, place them in the jre, and used the following.

 
SAXParserFactory factory = SAXParserFactory.newInstance();
        factory.setValidating(true);
        factory.setNamespaceAware(true);
   
        try {
            //Parse the input
            SAXParser saxParser = factory.newSAXParser();
            saxParser.setProperty(JAXP_SCHEMA_LANGUAGE,W3C_XML_SCHEMA);
            saxParser.setProperty(JAXP_SCHEMA_SOURCE,xmlSchameName);
        System.out.println("IS saxParser validating?:  " + saxParser.isValidating());
            saxParser.parse( new File(xmlFileName), handler);
        }
 
WITH=======
 
private final String JAXP_SCHEMA_LANGUAGE = 
    "http://java.sun.com/xml/jaxp/properties/schemaLanguage";
    private final String JAXP_SCHEMA_SOURCE = 
    "http://java.sun.com/xml/jaxp/properties/schemaSource";
    private final String W3C_XML_SCHEMA = "http://www.w3.org/2001/XMLSchema";

Forgot: If the file isn't valid and the void error(SAXException e) { } isn't overidden, then the file parses with the errors in it and you'll never know.

Thanks for the help in leading me in the right direction.



Joe
[ February 10, 2006: Message edited by: Joe Quickshot ]