XML Namespace Issues

[Tiago Fernandez]

Hello,

I'm trying to produce another XML from an existing XML using XSLT (XML + XSLT = XML), and I'm experiencing namespaces issue. I'm new to this, so I guess the solution might be easy, anyways I'm still confused about handling this.

Scenario A:
---
XML input:
<metadata xmlns="http://www.mycompany.com/schema/odsload" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

XML output:
Contains just data inside the XML input elements


Scenario B:
---
XML input:
<metadata xmlnsds="http://www.mycompany.com/schema/odsload" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

XML output:
Ok, I've got a well structured XML

Can anybody tell me please what's going on?

Thanks!

[Paul Clapham]

I suppose there is more code in your XSLT than you actually posted there. Probably it is trying to match on element names. When you match on an element name, you are trying to match that name with no namespace (that's an XPath 1.0 default). That fails to match that name in the default namespace, which is what's going on in the first example.

[Tiago Fernandez]

Thanks for replying Paul. Do you know a better solution for addressing this issue, once I can't modify the XML input? Adding "ds" to xmlns is definitely an ugly workaround

[Paul Clapham]

Instead of

<xsl:apply-template match="thing"/>

which doesn't match a "thing" element in the default namespace, you can do this:

<xsl:template match="*[name()='thing']"/>

That matches either a "thing" element in the default namespace or a "thing" element not in any namespace.
[ May 03, 2007: Message edited by: Paul Clapham ]