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SAXParseException  RSS feed

 
Milan Vasic
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Hi there this is my code:

<jsp:root xmlns:jsp="http://java.sun.com/JSP/Page" version="2.0">
<jsp:directive.page contentType="text/html; charset=UTF-8" />
<jsputput doctype-root-element="html"
doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
doctype-system="http://www.w3c.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">

some html code....


</html>
</jsp:root>


I still got the exception :org.xml.sax.SAXParseException: The markup in the document following the root element must be well-formed. Doeas anyone know why?
 
William Brogden
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There are methods in SAXParseException to get the line and column number that the parser objects to.

Bill
 
Milan Vasic
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Tnx Bill.

vaske
 
Milan Vasic
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I try to validate my jsp with a loot of on line validators, and my jsp is well formated, but when I try to parse that file with parse method on documentbuilder object I got this error.
 
William Brogden
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Have you been able to extract the line and column from the exception?
How is the jsp source code being generated?

Bill
 
It is sorta covered in the JavaRanch Style Guide.
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