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ques from overloading

 
gaurav nayyar
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What will happen if you try to compile and run this code.
class Rectangle{
public int area(int length , int width) {
return length * width;
}
}
class Square extends Rectangle{
public int area(long length , long width) {
return (int) Math.pow(length ,2);
}
}
class Test{
public static void main(String args[]) {
Square r = new Square();
System.out.println(r.area(5 , 4));
}
}
1. Will not compile.
2. Will compile and run printing out 20
3. Runtime error
4. Will compile and run printing out 25
the right answer is :1 how??? i can't get it
 
Jane Griscti
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Hi gaurav,
The methods area(int,int) and area(long, long) are ambiguous i.e. there is no way for the compiler to differentiate between the two as many values will satisfy both 'int' and 'long' parameters.
Hope that helps.
------------------
Jane Griscti
Sun Certified Programmer for the Java� 2 Platform
 
wei ma
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the problem is "r.area(5,4)" method call, the compiler will look for the four possible implmentation of this method.
area( int, int );
area( int, long );
area( long, int );
area( long, long );
in this case, the compiler found two implementations available, and it got cofused since it doesn't know which implementation you really want to invoke.
Wei
 
Namrata Shetty
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But i thought this would be a question of overloading. The compiler would take the most specific option
 
Jane Griscti
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It does involve overloading. The problem is overloading is resolved at compile-time and in this example the arguments being passed '5' and '4' can be used as both int's and long's so the compiler isnt' sure which overloaded method it should use.
Remember, the code is compiled to bytecode and this is the problem, should the compiler create the bytecode for <code>area(int,int)</code> or <code>area(long, long)</code>? If you change the call to <code>r.area( 5L, 4L )</code>, the code will compile. As it stands, the compiler can't tell what your intention is. If you only want to use 'int' types, remove the 'long' method. If you want to use both, remove the 'int' method.
Hope that helps.
------------------
Jane Griscti
Sun Certified Programmer for the Java� 2 Platform
 
Vanitha Sugumaran
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Hi,
If the two methods are in the same class then no error occurs. Why?

Thanks,
Vanitha.
 
Jane Griscti
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Hi Vanitha,
I think (but I'm not 100% sure) in the first example part of the problem is the compiler doesn't know wether to use the method in the Square class or the parent Rectangle class ie you've got an object 'r' which is both a Square and a Rectangle. Should the superclass behaviour be used or the subclass behaviour? The compiler doesn't know for sure.
When both methods are in the same class it doesn't really matter which is used; the object is a Square but in this case it has no behviours that are different from the superclass so it can be handled purely as a Rectangle ie there's no conflict between the class behaviours.
Hope that helps.
------------------
Jane Griscti
Sun Certified Programmer for the Java� 2 Platform
 
Vanitha Sugumaran
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Thanks for your explanation Jane, It is clear now.
Vanitha.
 
gaurav nayyar
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thanks to all of u now its clear
 
gaurav nayyar
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thanks to all of u now its clear
 
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