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# Math Doubt

Greenhorn
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Given this code snippet: double a = 14.9;
double b = method(a);
System.out.println(b);

If this snippet displays 15.0 in the standard output, what Math method(s) could method() have invoke?

a)ceil() and round()
b)floor() and round()
c)ceil() only
d)floor() only
e)round() only
This a question in barry bones mock exam(q no 31)
the answer is given as a .But i thgt the answer is c) and not a) because when ceil and round is used then the answer should me 15L and not 15.0.please explain.

Ranch Hand
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The reason why the answer is 'a' is:
The value is assigned to a double variable, therefore the long value of the round method (15L) will be automatically promoted to double (following the rules of widening conversion).
Hope this helps.
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Asma Zafar,
Sun Certified Programmer for Java2 Platform

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Hi,
I think ans c is correct since round () will return 15 not 15.0
Vanitha.

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Vanitha has a point there.

I remember from RoundUp Quiz that Math.round(double) will return a long, Math.round(float) will return an int.
However, I went and checked on the code in question and notice that the long return will implicitly be cast to double b.

Answer a will work in this case. Soo the winner is Asma
------------------
Percy Densmore
-SCJP2 Die Hard Student
[This message has been edited by Percy Densmore (edited September 08, 2001).]

Vanitha Sugumaran
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Hi all,
I am sorry I didn't see the line double b = method(a).
The first option will work too.
Vanitha.

Archana Nair
Greenhorn
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Hi

Even i didnt notice the line double b=method(a);
Anyway now my doubt is cleared with Asma's explanation.Thanx guys!
Archana

Greenhorn
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Originally posted by Vanitha Sugumaran:
Hi all,
I am sorry I didn't see the line double b = method(a).
The first option will work too.
Vanitha.

I think so