which will return all orders that have line items? a. select distinct o from Order o, IN(o.lineItems) li b. select distinct Object(o) from Order o, IN(o.lineItems) li c. select Object(o) from Order o where o.lineitems=0 d. select object(o) from Order o
the answer is b, d. but i think there is no answer. and a,c is incorrect and i can know why. but b,d also there is some problem as i think. on B, there is no 'where' clause, so the result is all order objects(no duplicate). on D is as same reason to b.but could be duplicated.
First of all, you need ALL orders that have lineitems. Orders with lineitems are a subset of all orders in the whole universe (database), so if you get ALL the orders there are, that will include all those having lineitems. That's why answer D is correct. You will never get duplicate orders, because of the DISTINCT keyword...
For answer B, the part "IN(o.lineItems) li" in the from clause makes the query look through each of the lineitems of each order. It lets "li" represent the Lineitem type instead of the collection type. So that EJB-QL returns only the orders that have lineitems.
posted 16 years ago
If you want to look young and thin, hang around old, fat people. Or this tiny ad:
Devious Experiments for a Truly Passive Greenhouse!