byte operations

[ppathak]

i dont know if this was posted earlier. if so plz let me know the link.
my q is
byte b=0;
b+=1;
// b = b+1;
b+=1: works & answer 1 is shown
b=b+1: doesnt work, it gives compile time error.
i understand y it gives error for b=b+1
but i dont understand y it gives 1 for b+=1;
could anyone clear this plz.
thx in adv.

[Ankur Gupta]

Following is from the JLS. Hope this clarifies ur doubt.
A compound assignment expression of the form E1 op= E2 is equivalent to E1 = (T)((E1) op (E2)), where T is the type of
E1, except that E1 is evaluated only once. Note that the implied cast to type T may be either an identity conversion (�5.1.1) or
a narrowing primitive conversion (�5.1.3). For example, the following code is correct:
short x = 3;
x += 4.6;
and results in x having the value 7 because it is equivalent to:
short x = 3;
x = (short)(x + 4.6);
Ankur

[ppathak]

thx Ankur,
i wonder what is JLS :-).

[satish]

JLS is Java Language Specification. You can download it from Sun's www.javasoft.com. JLS is like java LANGUAGE's bible.
Satish