Doubt

[Anonymous]

public class example {
int i[] = {0};
public static void main(String args[]) {
int i[] = {1};
change_i(i);
System.out.println(i[0]);
}
public static void change_i(int i[]) {
i[0] = 2;
i[0] *= 2;
}
}

IMO the answer should be 1, but the answer is . Is it because the method change_i is static and the changes happened in this method will be reflected in main(), but int i[]is not declared as static, how it can be 4 in main(). Please explain.

[Herbert Maosa]

Shallender,
I think the reason that the result reflects change in the value of i is because i is an array, and consequently an object.Recall that when you pass an object reference to a method, all changes made to that reference will be effected in the original object, since a reference is only an address in memory and any alterations are happening to the same location.This is contrary to the behaviour of primitives, passing primitives to methods passes a copy of the value.So this has nothing to do with the method being static, but with the fact that an array is a java object.
I hope this helps..
Herbert

[Anonymous]

Thanks Herbert,I understand the problem.
Shallender