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hi
please give me the correct explanation to questions which are mentioned below

Given the following code what will be the output?
class ValHold{
public int i = 10;
}
public class ObParm{
public static void main(String argv[]){
ObParm o = new ObParm();
o.amethod();
}
public void amethod(){
int i = 99;
ValHold v = new ValHold();
v.i=30;
another(v,i);
System.out.println(v.i);
}//End of amethod
public void another(ValHold v, int i){
i=0;
v.i = 20;
ValHold vh = new ValHold();
v = vh;
System.out.println(v.i+ " "+i);
}//End of another
}
1) 10,0, 30
2) 20,0,30
3) 20,99,30
4) 10,0,20
ans 4
What is the output of following if the return value is "the value 0 if the argument string is equal to this string; a value less than 0 if this string is lexicographically less than the string argument; and a value greater than 0 if this string is lexicographically greater than the string argument" (Assuming written inside main)
String s5 = "AMIT";
String s6 = "amit";
System.out.println(s5.compareTo(s6));
System.out.println(s6.compareTo(s5));
System.out.println(s6.compareTo(s6));
Ans
a> -32
32
0
b> 32
32
0
c> 32
-32
0
d> 0
0
0
Correct Answer is a)

 
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For your 1st question : http://www.javaranch.com/ubb/Forum24/HTML/001641.html
For your 2nd question :
Compares two Bytes numerically.
Returns the value 0 if the argument Byte is equal to this Byte; a value less than 0 if this Byte is numerically less than the Byte argument; and a value greater than 0 if this Byte is numerically greater than the Byte argument (signed comparison).
ASCII value of 'a' is ASCII value of 'A' + 32
Hope this helps.
 
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