Jane ur help is needed.....

[Aru Ven]

Hi Jane....
I am in trouble with the shift operators. I saw one of ur responses in a post ....... in which u have given some generalized formulas..... I tried to work it out...but could not... can u "PLEASE" give an example for EACH case with both positive & negative numbers.
Thanks in Advance.
Aruna

Left-shift:   16<<5 equivalent to 16 * 25
Right-shift:  16>>5 equivalent to 16 / 25
For the unsigned right shift operator >>>, if the number is positive, the result is the same as the right-shift
operator. If the number is negative the equivalent formula is:
-16 >>> 5 equiv to (16>>5) + ( 2<<~5)

[Pranav Jaidka]

hi Arun
Check out the following URL i think this will make things pretty clear to you about the way things work .
http://www.software.u-net.com/applets/BitShift/BitShiftAr.html

regards
pranav

[Jane Griscti]

Hi Aru,
The examples are '2 to the power of 5' not '25'.
Just for your peace of mind; I wrote the exam today and did not have to resort to knowing the formulas . The questions, for the most part, involved low values which were easy to work out it binary.
Hope that helps.
------------------
Jane
The cure for boredom is curiosity.
There is no cure for curiosity.
-- Dorothy Parker