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q 25 from tipsmart.com  RSS feed

 
Greenhorn
Posts: 6
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From TipSmart's sample paper
class MyClass
{
public static void main(String []args)
{
final int i = 100;
byte b = i;
System.out.println(b);
}
}
Here is the answer from website => Will compile and print 100
How come that we don't need to explicitly cast from int to byte?
Thank you for your clarification
 
Ranch Hand
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Because the int is final and so is a constant. The compiler can figure out the value at compile time and since 100 fits into a byte the compiler allows it. Anyone else want to clarify?
 
Ranch Hand
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My compiler issued approval
It does not compile without final
 
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