equalsIgnoreCase()...Strange

[Tanveer Mehmood]

Please note the line # 7. It prints true with argument as temp, but generates a compiler error if I modify it as;
System.out.println(s.equalsIgnoreCase("abc123"));
Anybody who can help me???
1. class StringFunctions
2. {
3. public static void main(String args[])
4. {
5. String s = new String("ABC123");
6. String temp = "abc123"; 7.System.out.println(s.equalsIngnoreCase(temp));
// System.out.prinltn(s.equalsIgnoreCase("abc123")); //generates error
8. }
9. }

[Cindy Glass]

The argument for the equalsIgnoreCase expects a String object which is out on the heap. If you feed it "abc123" you are feeding it a String literal, which is in the Constant Pool. As you can tell, the compiler handles the two slightly differently.

[Faiza Ayuub]

Whether you pass a string object or a string literal the code compiles perfectly well as it should. Cindy, by the way have you tried to compile it??

[Lisa Yanchunis]

There is a typo on line 7. prinltn instead of println

[Ali Haider]

Originally posted by Tanveer Mehmood:
Please note the line # 7. It prints true with argument as temp, but generates a compiler error if I modify it as;
System.out.println(s.equalsIgnoreCase("abc123"));
Anybody who can help me???
1. class StringFunctions
2. {
3. public static void main(String args[])
4. {
5. String s = new String("ABC123");
6. String temp = "abc123"; 7.System.out.println(s.equalsIngnoreCase(temp));
// System.out.prinltn(s.equalsIgnoreCase("abc123")); //generates error
8. }
9. }

Hi Tanveer
I have compiled the program n its running correctly. The result is:
true
true
But there r two spelling mistakes in the code which u have posted.
. In line 7 instead of writing equalsIgnoreCase, u have written equalsIngnoreCase.
. In the commented line, u have written System.out.prinltn, instead of System.out.println
Other than that the program is running fine.....
Regards
@li