JQ+ Question ID :957711112180

[huiying li]

import java.io.*;
import java.sql.*;
interface I1
{
   void m1() throws IOException;
}
interface I2
{
   void m1() throws SQLException;
}
public class Test35 implements I1, I2
{
    public static void main(String args[])
    {
       new Test35().m1();
    }
  
    public void m1()
    {
        System.out.println("Hi there");
    }
}

C:\JavaRanch>javac Test35.java
C:\JavaRanch>java Test35
Hi there
----------
The question was:
What methods have to be implemented by a class that says it implements I1 and I2 ?
The answer was:
There is no way that an method can declare an exception that satisfies both the methods.
As in my code, the class can declare no throws clause that will satisfy both interface method requirement.
Any thoughts?

[Hari Gangadharan]

I am a little confused here. Maybe I am not grasping the full question. The code you have written will compile properly. I do not think that java requires that your method should throw both the exceptions if you are implementing the interfaces I1 and I2. You will be implementing the interfaces if you follow the signature -- ie the parameters. Your method will decide what your method will throw.

------------------
Hari Gangadharan
Out of the turbulance a soft voice spoke to me ...
Son smile and be happy things could be worse...
I smiled and I was happy and things became worse!

[Subramaniam Venkatesan]

the code will compile since there is no ambiguity.
Ambiguity will arise when you throw some exception in this case.
Similarly there would not be any compile err, when the
same variable is declared in these interfaces but not used in the sub class.. ambiguity will arise when we use the variable in the subclass.