forDigit ()?????

[rajashree ghatak]

what does the following forDigit() method return.
static char forDigit(int num,int radix)
According to what i have read it returns the digit character associated with the value of num.
The following is the code:
int num=49;
char ch2=Character.forDigit(num,10);
System.out.println(ch2);
According to me, 1 should be the output but nothing is getting printed,though no compile error is generated.could anyone tell what is wrong with this code?
thanx in advance.

[sai challa]

Hello i found this piece of info in JLS .Hope this helps.
"
20.5.24 public static char forDigit(int digit, int radix)
Returns a character that represents the given digit in the specified radix. If the value of radix is not a valid radix, or the value of digit is not a valid digit in
the specified radix, the null character '\u0000' is returned.
A radix is valid if and only if its value is not less than Character.MIN_RADIX (2) and not greater than Character.MAX_RADIX (36).
"A digit is valid if and only if it is nonnegative and less than the radix."
If the digit is less than 10, then the character value '0'+digit is returned; otherwise, 'a'+digit-10 is returned. Thus, the digits produced by forDigit, in
increasing order of value, are the ASCII characters:
0123456789abcdefghijklmnopqrstuvwxyz "
Since a digit is valid if and only if it is non-negative and less than radix,in your case 49 is greater than 10 and hence is an invalid digit and a null character is returned.