• Post Reply Bookmark Topic Watch Topic
  • New Topic
programming forums Java Mobile Certification Databases Caching Books Engineering Micro Controllers OS Languages Paradigms IDEs Build Tools Frameworks Application Servers Open Source This Site Careers Other Pie Elite all forums
this forum made possible by our volunteer staff, including ...
Marshals:
  • Tim Cooke
  • Campbell Ritchie
  • Ron McLeod
  • Junilu Lacar
  • Liutauras Vilda
Sheriffs:
  • Paul Clapham
  • Jeanne Boyarsky
  • Henry Wong
Saloon Keepers:
  • Tim Moores
  • Tim Holloway
  • Stephan van Hulst
  • Piet Souris
  • Carey Brown
Bartenders:
  • Jesse Duncan
  • Frits Walraven
  • Mikalai Zaikin

Assigning a final int to a byte ???

 
Ranch Hand
Posts: 18944
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator
Hello,
Why will the code below compile, but if "final" is taken out it won't? What is the principle?
Thanks so much,
Emerald
class Test
{
public static void main(String []args)
{
final int i = 100;
byte b = i;
System.out.println(b);
}
}
 
Ranch Hand
Posts: 241
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator
By making i final you are declaring to the compiler that it is a constant. Since the value of i can never change, and you can fit i's value of 100 into a byte, the compiler allows it. If i is not a constant (i.e., you remove "final"), the compiler complains.
Art
 
pie. tiny ad:
Building a Better World in your Backyard by Paul Wheaton and Shawn Klassen-Koop
https://coderanch.com/wiki/718759/books/Building-World-Backyard-Paul-Wheaton
reply
    Bookmark Topic Watch Topic
  • New Topic