JQ+ Question ID :952739443290

[Greg Georges]

Have a question
Given the following code fragment, which of the following lines would be a part of the output?
outer:
for ( int i = 0 ; i<3 ; i++ )
{
for ( int j = 0 ; j<2 ; j++ )
{
if ( i == j )
{
continue outer;
}
System.out.println( "i=" + i + " , j=" + j );
}
}
Given the following code fragment, which of the following lines would be a part of the output?
a) i=1, j=0
b) i=0, j=1
c) i=1, j=2
d) i=2, j=1
e) i=2, j=2
This is easy but It says there are only 2 good answers but I thought there were three, the answers are A and C, but I was sure that B could also be an answer. Can anyone explain why B is not an answer?

[Kevin Yip]

i takes value 0, 1 & 2; j takes value 0 & 1.
Whenever i == j, the inside loop will stop and the program continue with the outer loop starting with the next value of i.
Starting with i == 0:
(i==0,j==0) ---> not printed, next i
(i==1,j==0) ---> get printed
(i==1,j==1) ---> not printed, next i
(i==2,j==0) ---> get printed
(i==2,j==1) ---> get printed
Loop ends.
So output are:
i=1 , j=0
i=2 , j=0
i=2 , j=1
So correct options should be A and D.

[Kishore Pamu]

Hi!Greg,
I compiled your program and got the output
as
i=1,j=0
i=2,j=0
i=2,j=1
the answer b is wrong.According to the program
firt i=0 and j=0
the if conditons becomes true and again it goes to Outer
then i=1 and j=0 the if condition returns false and i=1,j=0 is printed.
now j value is incrimented and becomes j=1 the if conditon returns true so it continues outer then
now i=2 and j=0 the if condition returns false and i=2,j=0 is printed
now j value is incremented and becomes j=1 theif conditon returns false and i=2,j=1 is printed.
now control goes to for loop jis incremented to 2
now the if condition returns true and it continues outer
and the progam terminates.
Hope this helps!.

[Greg Georges]

Thanks everyone, did not follow the continue correctly and that is why I was getting B in the answer, thanks again, next time I will be more careful with the continue statements

[Prasanna Wamanacharya]

Hi Greg,
Option b is i=0, j=1
In the first iteration, value of i & j are 0 & 0. The code says,

   if ( i == j ) 
     {
        continue outer;
     }

The "outer" label is at the beginning of outer loop. So the further iterations of the inner loop are skipped, i is assigned the value 1, and the iteration proceeds.
So, the values given in option b are incorrect.
If continue statement was present without any label, or if the label was placed at the beginning of the inner loop(both are equivalent), then option b would have been one of the correct options.
Although they may seem very easy on the first glance, codes concerned with flow control are very tricky, and it is a good idea to go through each iteration one by one, to be absolutely sure of the answer.
I hope this clears your doubt. Any comments are welcome.
Prasanna.