byte

[Susie Chow]

Hi,
Why does the follow code result 1.
byte b = 0;
b += 1;
But the follow code need a cast?
byte a=0;
byte b=1;
byte c = (byte)(a+b);
Thank you.

[Sandeep Nachane]

Expression b += 1; is evaluated as
b = (byte)(b +1);
Hence it does not complain, as the cast is put for you by the compiler.
In your second code snippet.
byte c = (a+b);
Both a and b are promoted to int (numeric binary promotion) so the expression becomes
c = (int)a + (int)b;
If you do not cast it to byte, it becomes an error since you are trying to store int value in byte variable (i.e c)
-Sandeep Nachane
www.tipsmart.com

[This message has been edited by Sandeep Nachane (edited July 13, 2001).]