[constructor]...

[chao-long liao]

class A{
int x = 0;
A(int w){
x = w;
}
}
class B extends A{
int x = 0;
B(int w){
x = w +1;
}
}
What's wrong with the code???
---------------------------------
thanks for help, Liao

[Guoqiao Sun]

Hi, there is no no-argument constructor in the superclass A, as a result, when the implicit call to super() from constructor in class B happens, there will be a compile time error.
Hope it helps.
Guoqiao

Originally posted by chao-long liao:
class A{
int x = 0;
A(int w){
x = w;
}
}
class B extends A{
int x = 0;
B(int w){
x = w +1;
}
}
What's wrong with the code???

[Andre Zhang]

Hi,
that's because the constructor B(int w) invokes super() implicitly. & after u define A(int w) only, there'll be no constructor of A with no arguments. this causes a compile time error.
if u change the code a little, it will be OK.
class A{
int x = 0;
A (int w){
x = w;
}
}
class B extends A{
int x = 0;
B(int w){
super(w);
x = w +1;
}
}