Can some explain it to me please?

[Ragu Sivaraman]

public class Test028 extends Object
{
final int y; //1

public Test028() {
y = 0; //2
}

public Test028(int val) {
y = 1; //3
}
}
It just compiles and runs fine.
Explanation gives for the answer is little unclear to me
Can some one share your thoughts pleaseeeee?
thankx

[leena rane]

Hi Raghu,
this is what i think,
final int y;
since this is not a static variable,either it should be given value in the decalration.
i.e. final int y=7;
or should be given value in every constructor.
But if it is static, it can be given value in static block.

[This message has been edited by leena rane (edited September 05, 2001).]

[Anonymous]

Ragu,
I am not sure of what exactly your question is...but go through this and see if it helps.

The value of Final variables cannot be changed once initialized.But they can be declared as "y" has been at //1 in your code(Add Leena's Explanation here ...easy for me). I have made a few modifications to your program...Do take a look.

class test{
 final int y; //1
 public test(){
 y = 5; //2
 }
 public test(int val){
 y = 1; //3
 }
// This method will generate a compile-time error as 
//it is trying to reset the value of a final variable.

/* void sety(int val){
   y = val;
 } */
}
 
public class test1{
   public static void main(String[] args){
   test a = new test();  // *4* This statement when used will print out 5.
   test a = new test(3); // *5* This statement when used will print out 0.
   System.out.println(a.y);
   }
}

Another point is...If you don't comment out either //*4* or //*5*, you'll get a compile-time error. To be more precise, having them both means that you are invoking //*5* after //*4* has been executed, thus trying to reset the value of y (which is illegal).
Cheers!
Shyam
[This message has been edited by Thomas Paul (edited September 07, 2001).]
[This message has been edited by Shyamsundar Gururaj (edited September 08, 2001).]

[Marilyn de Queiroz]

I think this line:
test a = new test(3); // *5* This statement when used will print out 0.
will print 1 and not 0

class test{
 final int y; //1
 public test(){
 y = 5; //2
 }
 public test(int val){
 y = 1; //3
 }
// This method will generate a compile-time error as 
//it is trying to reset the value of a final variable.

/* void sety(int val){
   y = val;
 } */
}
 
public class test1{
   public static void main(String[] args){
   test a = new test();  // *4* This statement when used will print out 5.
   test a = new test(3); // *5* This statement when used will print out 0.
   System.out.println(a.y);
   }
}

[This message has been edited by Thomas Paul (edited September 07, 2001).]

[Anonymous]

Marilyn is right...
That was a typo...sorry about that.
Thanks
Shyam