hibernate sample done but no record inserted

[Alan Hermin]

hi all..
i am using good resource as first sample to lern hibernate, i use This URL
,the sample is great to read and understand as beginner..
this sample is compile and OK...

BUT No Record Inserted at my Contact Table,,,,Why??

regards

[Paul Sturrock]

Did you close or flush the Session? Did you commit the transaction? (if you used one?)

[Alan Hermin]

hi , yes i did, i flushed and closed the session by saying:

  
      session.flush();
      session.close();

still no record added, can you help me?
[ December 19, 2006: Message edited by: Ala'a Hendi ]

[Paul Sturrock]

...and did you commit the transaction (if you used one)? Were there any exception messages?

[Alan Hermin]

this is the code:

  
package roseindia.tutorial.hibernate;
 
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.Transaction;
import org.hibernate.cfg.Configuration;
 

/**
 * @author Deepak Kumar
 *
 * <a href="http://www.roseindia.net" target="_blank" rel="nofollow">http://www.roseindia.net</a>
 * Hibernate example to inset data into Contact table
 */
public class FirstExample {
  public static void main(String[] args) 
  {
    Session session = null;
 
    try{
      // This step will read hibernate.cfg.xml and prepare hibernate for use
      SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
       session =sessionFactory.openSession();
       
              
        //Create new instance of Contact and set values in it by reading them from form object
         System.out.println("****************(Inserting Record)****************");         
        Contact contact = new Contact();
        contact.setId(3);
        contact.setFirstName("mohammed");
        contact.setLastName("alaa");
        contact.setEmail("[e-mail]");        
        session.save(contact);
     
        System.out.println("Done");
    }catch(Exception e){
      System.out.println("Exception.......: "+e.getMessage());
    }finally{
      // Actual contact insertion will happen at this step
      session.flush();
      session.close();
      }
    
  }
} 
  

anyway, there is no exception......

[Paul Sturrock]

Have you enabled Hibernate's debugging to see what SQL it generates? If not, try that.

[Ayub ali khan]

Hi,

I executed the same code after the addition of transaction. Modify accordingly.

public class TestHibernate {

public static void main(String[] args) {

Session session = null;

try{
// This step will read hibernate.cfg.xml and prepare hibernate for use
SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
session =sessionFactory.openSession();
org.hibernate.Transaction tx = session.beginTransaction();

//Create new instance of Contact and set values in it by reading them from form object
System.out.println("Inserting Record");
UAPUser user=new UAPUser();

//user.setId(2);
user.setPassword("abc");
user.setUserName("User1");
session.save(user);
tx.commit();

System.out.println("Done");
}catch(Exception e){
System.out.println(e.getMessage());
}finally{
// Actual contact insertion will happen at this step
session.flush();
session.close();

}

}

}

[Alan Hermin]

thanks...
now it works..
thanks very much