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Expalin the answer -- Arrays  RSS feed

 
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19. If size = 4, triArray looks like:

int[][] makeArray( int size)
{ int[][] triArray = new int[size] [];
int val=1;
for( int i = 0; i < triArray.length; i++ )
{ triArray[i] = new int[i+1];
for( int j=0; j < triArray[i].length; j++ )
{ triArray[i][j] = val++;
}
}
return triArray;
}

a)
1 2 3 4
5 6 7
8 9
10
b)
1 4 9 16
c)
1 2 3 4
d)
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
e)
1
2 3
4 5 6
7 8 9 10
 
Gold Digger
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I think the right answer is e...
Try and run it but at a first sight e seems to be the right answer...
Val
 
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When you run it
it prints
1
2
3
4
5
6
7
8
9
10
So is both a and e correct?
I am confused
Can someone explain how the code is working?
Thankx
 
Valentin Crettaz
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it's not a matter of printing it is a matter of HOW the arrays look like...
the first array has one element: 1
the second array has two elements: 2 3
the third array has three elements: 4 5 6
the fourth array has four elements: 7 8 9 10
so answer e is correct !!
Val
 
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Originally posted by Roopa Bagur:
19. If size = 4, triArray looks like:

int[][] makeArray( int size)
{ int[][] triArray = new int[size] [];
int val=1;
for( int i = 0; i < triArray.length; i++ )
{ triArray[i] = new int[i+1];
for( int j=0; j < triArray[i].length; j++ )
{ triArray[i][j] = val++;
}
}
return triArray;
}

a)
1 2 3 4
5 6 7
8 9
10
b)
1 4 9 16
c)
1 2 3 4
d)
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
e)
1
2 3
4 5 6
7 8 9 10


 
Valentin Crettaz
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Good job Amit !!
Val
 
Roopa Bagur
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Excellent everybody thankyou

Originally posted by Roopa Bagur:
19. If size = 4, triArray looks like:

int[][] makeArray( int size)
{ int[][] triArray = new int[size] [];
int val=1;
for( int i = 0; i < triArray.length; i++ )
{ triArray[i] = new int[i+1];
for( int j=0; j < triArray[i].length; j++ )
{ triArray[i][j] = val++;
}
}
return triArray;
}

a)
1 2 3 4
5 6 7
8 9
10
b)
1 4 9 16
c)
1 2 3 4
d)
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
e)
1
2 3
4 5 6
7 8 9 10


 
It is sorta covered in the JavaRanch Style Guide.
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