how to invoke a webservice

[Ajay Chawla]

Hi,
I need to know what needs to be done to invoke a web service? In other words what are the basics for writing a web service client?
Thanks
Ajay

[Balaji Loganathan]

Only few things,

Download Apache Axis

Read the documentation on using the pretty-tiny tool WSDL2Java

Its a tool which will automatically create the necessary java files (stubs)to for a given webservice(WSDL)

compile the java files, you can also import the necessary class to your application

run it.

[Ajay Chawla]

Thanks Balaji,
Actually I need to do it without any tool.
I've to use SOAP API. I think I can do it using Call().
Can u tell me what I need to specify in Call.setTargetObjectURI()? is it the Web service name or some other identifier?
Ajay

[Ajay Chawla]

Iam getting the following fault when i run my client : -
faultcode :soap:Client
faultString :Server did not recognize the value of HTTP Header SOAPAction:
my code is : -
Call call = new org.apache.soap.rpc.Call();
URL url = new URL("http://delgtel304:7070/WebService2/JavaService1.asmx");
call.setTargetObjectURI"http://delgtel304:7070/WebService2/JavaService1.asmx");
call.setMethodName("JavaTest");
call.setEncodingStyleURI(org.apache.soap.Constants.NS_URI_SOAP_ENC);
Vector vParam = new Vector();
vParam.addElement(new org.apache.soap.rpc.Parameter"str",String.class,"Ajay",null));
call.setParams(vParam);
org.apache.soap.rpc.Response resp = call.invoke(url, "");

if(resp.generatedFault()){
org.apache.soap.Fault fault = resp.getFault();
System.out.println("faultcode :"+fault.getFaultCode());
System.out.println("faultString :"+fault.getFaultString());
}
else{
org.apache.soap.rpc.Parameter result = resp.getReturnValue();
System.out.println(result.getValue());
}
any help is greatly appreciated.
Thanks

[Lasse Koskela]

Apparently your code is not setting the SOAP-Action header. You can do it with

call.setProperty(javax.xml.rpc.Call.SOAPACTION_USE_PROPERTY, new Boolean(true));
call.setProperty(javax.xml.rpc.Call.SOAPACTION_URI_PROPERTY, "MySoapAction");

[ March 10, 2004: Message edited by: Lasse Koskela ]

[Jeroen Wenting]

Originally posted by Balaji Loganathan:
Read the documentation on using the pretty-tiny tool WSDL2Java

How to get WSDL2Java to work though... Whenever I try I get an error

C:\work\Java\SOAP\zip>java -cp %AXISCP% org.apache.axis.wsdl.WSDL2Java ZipServic
e.wsdl
Exception in thread "main" java.lang.NoClassDefFoundError: javax.wsdl.Definition
at org.apache.axis.wsdl.toJava.JavaGeneratorFactory.class$(JavaGeneratorFactory.java:163)
at org.apache.axis.wsdl.toJava.JavaGeneratorFactory.addDefinitionGenerators(JavaGeneratorFactory.java:163)
at org.apache.axis.wsdl.toJava.JavaGeneratorFactory.addGenerators JavaGeneratorFactory.java:133)
at org.apache.axis.wsdl.toJava.JavaGeneratorFactory.<init> JavaGeneratorFactory.java:120)
at org.apache.axis.wsdl.toJava.Emitter.<init>(Emitter.java:120)
at org.apache.axis.wsdl.WSDL2Java.createParser(WSDL2Java.java:172)
at org.apache.axis.wsdl.gen.WSDL2.<init>(WSDL2.java:113)
at org.apache.axis.wsdl.WSDL2Java.<init>(WSDL2Java.java:161)
at org.apache.axis.wsdl.WSDL2Java.main(WSDL2Java.java:289)

AXISCP is

AXISCP=c:\tools\axis-1_1\lib\axis.jar;c:\tools\axis-1_1\lib\commons-discovery.jar;c:\tools\axis-1_1\lib\commons-logging.jar;c:\tools\axis-1_1\lib\log4j-1.2.8.jar;c:\tools\axis-1_1\lib\jaxrpc.jar;c:\tools\axis-1_1\lib\saaj.jar

added some linebreaks to keep it readable
other than that the classpath is empty so no conflicting libraries.
Using J2SDK 1.4.2-b28 (I know Axis has trouble with 1.4 JDKs, but I suppose there must be a workaround?)

[Lasse Koskela]

You need the wsdl4j.jar in your classpath as well (if I remember correctly, that's where the javax.wsdl package is defined).

[Jeroen Wenting]

cheers. Sometimes you just don't see your own mistakes however long you stare at them

[Ajay Chawla]

Hi All,
Thanks for all those reply's.
But my problem still remains but now in a different form.
I modified the code as: -
System.setProperty("javax.xml.soap.MessageFactory","weblogic.webservice.core.soap.MessageFactoryImpl");
System.setProperty( "javax.xml.rpc.ServiceFactory","weblogic.webservice.core.rpc.ServiceFactoryImpl");
ServiceFactory factory = ServiceFactory.newInstance();
String targetNamespace = "http://tempuri.org/";
QName serviceName = new QName(targetNamespace,"JavaService1");
QName portName = new QName(targetNamespace,"JavaService1Soap");
QName operationName = new QName("http://schemas.xmlsoap.org/soap/http","JavaTest");
URL wsdlLocation = new URL("http://delgtel304:7070/WebService2/JavaService1.asmx?WSDL");
Service service = factory.createService(wsdlLocation, serviceName);
Call call = service.createCall(portName, operationName);
call.setProperty(javax.xml.rpc.Call.SOAPACTION_USE_PROPERTY, new Boolean(true));
call.setProperty(javax.xml.rpc.Call.SOAPACTION_URI_PROPERTY, "MySoapAction");
String result = (String) call.invoke(new Object[] {"BEAS"});
System.out.println("\n");
System.out.println("This example shows how to create a dynamic client application that invokes a non-WebLogic Web service.");
System.out.println("The webservice used was:http://services.xmethods.net/soap/urn:xmethods-delayed-quotes.wsdl");
System.out.println("The quote for BEAS is: ");
System.out.println(result);

I get this on console :-
WARNINIG: Unable to find a javaType for the xmlType:['http://tempuri.org/']:Java
Test. Make sure that you have registered this xml type in the type mapping
Using SOAPElement instead
WARNINIG: Unable to find a javaType for the xmlType:['http://tempuri.org/']:Java
TestResponse. Make sure that you have registered this xml type in the type mappi
ng
Using SOAPElement instead
Exception in thread "main" javax.xml.rpc.JAXRPCException: failed to invoke opera
tion. Error in the soap layer (jaxm); nested exception is: Message[ failed to se
rialize xml:weblogic.xml.schema.binding.SerializationException: mapping lookup f
ailure. class=interface javax.xml.soap.SOAPElement class context=TypedClassConte
xt{schemaType=['http://tempuri.org/']:JavaTest}]StackTrace[
javax.xml.soap.SOAPException: failed to serialize xml:weblogic.xml.schema.bindi
ng.SerializationException: mapping lookup failure. class=interface javax.xml.soa
p.SOAPElement class context=TypedClassContext{schemaType=['http://tempuri.org/']
:JavaTest}
at weblogic.webservice.core.DefaultPart.toXML(DefaultPart.java:266)
at weblogic.webservice.core.DefaultMessage.toXML(DefaultMessage.java:456
)
at weblogic.webservice.core.DefaultOperation.invoke(DefaultOperation.jav
a:407)
at weblogic.webservice.core.DefaultOperation.invoke(DefaultOperation.jav
a:363)
at weblogic.webservice.core.rpc.CallImpl.invoke(CallImpl.java:423)
at weblogic.webservice.core.rpc.CallImpl.invoke(CallImpl.java:292)
at TestClient2.main(TestClient2.java:35)
Caused by: weblogic.xml.schema.binding.SerializationException: mapping lookup fa
ilure. class=interface javax.xml.soap.SOAPElement class context=TypedClassContex
t{schemaType=['http://tempuri.org/']:JavaTest}
at weblogic.xml.schema.binding.RuntimeUtils.lookup_serializer(RuntimeUti
ls.java:144)
at weblogic.xml.schema.binding.RuntimeUtils.invoke_serializer(RuntimeUti
ls.java:180)
at weblogic.xml.schema.binding.RuntimeUtils.invoke_serializer(RuntimeUti
ls.java:167)
at weblogic.webservice.core.DefaultPart.toXML(DefaultPart.java:258)
... 6 more
]
at weblogic.webservice.core.rpc.CallImpl.invoke(CallImpl.java:432)
at weblogic.webservice.core.rpc.CallImpl.invoke(CallImpl.java:292)
at TestClient2.main(TestClient2.java:35)
Thanks
Ajay

[Vishwa Kumba]

Did anybody solve this problem?. I am getting a similar error in Weblogic 8.1, when trying to invoke a web service with JAX-RPC (dynamic wsdl method).

[Niral Trivedi]

Hi,

I am also having similar problem when trying to connect to a WS using Axis client.

Can somebody tell me what should be the value for

 Call.SOAPACTION_URI_PROPERTY 

? I tried setting it to blank and some other value but I get this error regardless. What is the significance of this property?

Thanks