class Q4 {
public static void main(
String args[]) {
for(int i = 0; i<2; i++) {
continue; //break wont compile too
System.out.println("Byte");
}
}
}
It doesnt compile "unreachable stmt". I understood the reason
My question is... Does the compiler always gives error if it finds a stmt not being reachable?
Any idea
Ragu
