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JTip Question

 
Ranch Hand
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<code><pre>
class Process {
byte b=127;
Process() {
this.methodA();
}
void methodA() {
System.out.println("Process:MethodA() - Value of b is = " + b );
}
public static void main(String [] args) {
Processor p = new Processor();
}
}
class Processor extends Process {
byte b=126;
Processor() {
System.out.println("Processor:Constructor - Value of b = " + b);
}
void methodA() {
System.out.println("Processor:MethodA() - Value of b = " + this.b);
}
}
</pre>
</code>
Can someone explain why the output is 0 and 126.
Thanks
 
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<code><pre>
class Process {
byte b=127;
Process() {
this.methodA();
}
This method didn't get called
void methodA() {
System.out.println("Process:MethodA() - Value of b is = " + b );
}
public static void main(String [] args) {
Processor p = new Processor();
}
}
class Processor extends Process {
byte b=126;
Processor() {
System.out.println("Processor:Constructor - Value of b = " + b);
}
Instead this method get called
void methodA() {
System.out.println("Processor:MethodA() - Value of b = " + this.b);
}
}
</pre>
</code>
Can someone explain why the output is 0 and 126.

Since Processor.b didn't get a chance to init thats why output is 0.
Since at runtime the actually Object's method get called thats why Processor method get called.
 
It is sorta covered in the JavaRanch Style Guide.
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