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Tomcat Installation

 
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Hi,
I have downloaded tomcat3.2.1 but couldn't install it properly. I unzipped it in c:\jakarta-tomcat\...
On my system Java is installed in C;\JDK1.3, so in startup.bat and shutdown.bat,after the line
if not "%TOMCAT_HOME%" == "" goto start
I added the two lines:
SET JAVA_HOME=C:\JDK1.3
SET TOMCAT_HOME=C:\jakarta-tomcat
and made the same changes to shutdown.bat.
After this, In autoexec.bat I have set the path:
SET PATH=c:\jdk1.3\jre\lib;c:\jdk1.3\jre\bin;c:\jdk1.3\bin;
I added and updated the CLASSPATH:
C:\jakarta-tomcat\lib\servlet.jar
C:\jakarta-tomcat\lib\jasper.jar
After creating shorcut of startup and shutdown.bat and setting their memory to 4096,when I clicked on the startup icon I got some error message like:
Unable to set CLASSPATH dynamically.
Note: To set the CLASSPATH dynamically on Win9x systems
only DOS 8.3 names may be used in TOMCAT_HOME!
Setting your CLASSPATH statically.
Using CLASSPATH: C:\JAKARTA-TOMCAT\JAKARTA-TOMCAT-3.2.1\classes;C:\JAKARTA-TOMCA
T\JAKARTA-TOMCAT-3.2.1\lib\ant.jar;C:\JAKARTA-TOMCAT\JAKARTA-TOMCAT-3.2.1\lib\ja
sper.jar;C:\JAKARTA-TOMCAT\JAKARTA-TOMCAT-3.2.1\lib\jaxp.jar;C:\JAKARTA-TOMCAT\J
AKARTA-TOMCAT-3.2.1\lib\parser.jar;C:\JAKARTA-TOMCAT\JAKARTA-TOMCAT-3.2.1\lib\se
rvlet.jar;C:\JAKARTA-TOMCAT\JAKARTA-TOMCAT-3.2.1\lib\webserver.jar;;C:\jdk1.2.2\
lib\tools.jar ;C:\jdk1.3\lib\tools.jar;C:\JDK1.3\lib\tools.jar
Starting Tomcat in new window
Bad command or file name
What is the problem? Please help....
thanx
 
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Hi.
You must not modify startup.bat or anything in bin directory.
What you have modify -among other things- workers.properties in conf directory. There you declare the path to your jdk installation and your tomcat installation.
Since installing Tomcat is not so easy, I advise you to read installation.html that is in the doc directory.

Originally posted by Neeta Tripathi:
Hi,
I have downloaded tomcat3.2.1 but couldn't install it properly. I unzipped it in c:\jakarta-tomcat\...
On my system Java is installed in C;\JDK1.3, so in startup.bat and shutdown.bat,after the line
if not "%TOMCAT_HOME%" == "" goto start
I added the two lines:
SET JAVA_HOME=C:\JDK1.3
SET TOMCAT_HOME=C:\jakarta-tomcat
and made the same changes to shutdown.bat.
After this, In autoexec.bat I have set the path:
SET PATH=c:\jdk1.3\jre\lib;c:\jdk1.3\jre\bin;c:\jdk1.3\bin;
I added and updated the CLASSPATH:
C:\jakarta-tomcat\lib\servlet.jar
C:\jakarta-tomcat\lib\jasper.jar
After creating shorcut of startup and shutdown.bat and setting their memory to 4096,when I clicked on the startup icon I got some error message like:
Unable to set CLASSPATH dynamically.
Note: To set the CLASSPATH dynamically on Win9x systems
only DOS 8.3 names may be used in TOMCAT_HOME!
Setting your CLASSPATH statically.
Using CLASSPATH: C:\JAKARTA-TOMCAT\JAKARTA-TOMCAT-3.2.1\classes;C:\JAKARTA-TOMCA
T\JAKARTA-TOMCAT-3.2.1\lib\ant.jar;C:\JAKARTA-TOMCAT\JAKARTA-TOMCAT-3.2.1\lib\ja
sper.jar;C:\JAKARTA-TOMCAT\JAKARTA-TOMCAT-3.2.1\lib\jaxp.jar;C:\JAKARTA-TOMCAT\J
AKARTA-TOMCAT-3.2.1\lib\parser.jar;C:\JAKARTA-TOMCAT\JAKARTA-TOMCAT-3.2.1\lib\se
rvlet.jar;C:\JAKARTA-TOMCAT\JAKARTA-TOMCAT-3.2.1\lib\webserver.jar;;C:\jdk1.2.2\
lib\tools.jar ;C:\jdk1.3\lib\tools.jar;C:\JDK1.3\lib\tools.jar
Starting Tomcat in new window
Bad command or file name
What is the problem? Please help....
thanx



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