Win a copy of The Journey To Enterprise Agility this week in the Agile and Other Processes forum! And see the welcome thread for 20% off.
  • Post Reply Bookmark Topic Watch Topic
  • New Topic
programming forums Java Mobile Certification Databases Caching Books Engineering Micro Controllers OS Languages Paradigms IDEs Build Tools Frameworks Application Servers Open Source This Site Careers Other all forums
this forum made possible by our volunteer staff, including ...
Marshals:
  • Jeanne Boyarsky
  • Liutauras Vilda
  • Campbell Ritchie
  • Tim Cooke
  • Bear Bibeault
Sheriffs:
  • Paul Clapham
  • Junilu Lacar
  • Knute Snortum
Saloon Keepers:
  • Ron McLeod
  • Ganesh Patekar
  • Tim Moores
  • Pete Letkeman
  • Stephan van Hulst
Bartenders:
  • Carey Brown
  • Tim Holloway
  • Joe Ess

Boolean Output?  RSS feed

 
Ranch Hand
Posts: 435
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
public class TestClass
{
public static void main(String args[ ] )
{
int i = 0 ;
boolean bool1 = true ;
boolean bool2 = false;
boolean bool = false;
bool = ( bool2 & method1(i++) ); //1
bool = ( bool2 && method1(i++) ); //2
bool = ( bool1 | method1(i++) ); //3
bool = ( bool1 || method1(i++) ); //4
System.out.println(i);
}
public static boolean method1(int i)
{
return i>0 ? true : false;
}
}

Can any one tell me the output? and the reason for that?
Sonir
 
Author
Ranch Hand
Posts: 121
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
Hello !
The best way would by to try it out. I guess the answer is "2".
Reason:
"i" will only change its value with the evaluation of "method1(i++)". This term is not evaluated in //2 and //4 due to short circuit evaluation of && (||) and the value of bool2 (bool1). It is evaluated in //1 and //3, 0+1+1=2. The statements in the method do not harm, 'cause && and || are evaluated left to right.
But as I said, try it out. It's the best way to understand what's going on. add a "System.out.println(i)" after each assignment to bool.
Greetings from Euroland,
Stefan
 
Ranch Hand
Posts: 464
  • Mark post as helpful
  • send pies
  • Quote
  • Report post to moderator
good question sonir...
i++, post increment ... so i sends its current values as the parameter to the method and then increments itself..
In the short circuit operations.. RHS never gets executed , so we save couple of computations resulting the value of i to be '2'
Is it helpful?
Ragu
 
  • Post Reply Bookmark Topic Watch Topic
  • New Topic
Boost this thread!