SubClass??

[sonir shah]

class Super
{
public int getNumber( int a)
{
return 2;
}
}
public class SubClass extends Super
{
public int getNumber( int a, char ch)
{
return 4;
}
public static void main(String[] args)
{
System.out.println( new SubClass().getNumber(4) );
}
}
Ans : 2
I ran the program it gave me the above ans.
But I am confused, since in the main , it is calling the SubClass, it should print 4
Please explain.
Sonir

[Rashmi Tambe]

Sohir,
Have a look at method prototype. It is getNumber(int) and not GetNumber(int, char) . so the super class method is called.
HIH
Rashmi

[Nisheeth Kaushal]

Hi,
Can u please explain the use of new statement here.
Are we using it b'coz we are making static reference to method int getNumber(int) in class Super.
Please reply early,
thanx in advance,
Nisheeth

[Rob Ross]

No, there's no static method being invoked. You're creating a new SubClass object because you want to invoke its getNumber() method. Because getNumber() is NOT static, you can't just call "getNumber()", you can only call it on an actual class instance. That's why the new SubClass() statement is there. This is just a shorthand way of writing
SubClass aSubClassInstance = new SubClass();
System.out.println( aSubClassInstance.getNumber(4) );

Rob