qunlbao leon

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Younes Essouabni

Ranch Hand

Posts: 479

posted 15 years ago

I assume that you know what the >> operator do.

In fact if the right hand side operator is 32, it just do nothing.

The explanation come from the modulo.

32 modulo 32 =0 so do nothing.

32 modulo 31 =31 so do 31

32 modulo 33 =1 so do 1.

So if you do

int >> 33 or int >>1 it just do the same thing.

I hope my explanation is helpfull!!!

If not,do not hesitate to contact me.

Sorry for my english

In fact if the right hand side operator is 32, it just do nothing.

The explanation come from the modulo.

32 modulo 32 =0 so do nothing.

32 modulo 31 =31 so do 31

32 modulo 33 =1 so do 1.

So if you do

int >> 33 or int >>1 it just do the same thing.

I hope my explanation is helpfull!!!

If not,do not hesitate to contact me.

Sorry for my english

Younes

By constantly trying one ends up succeeding. Thus: the more one fails the more one has a chance to succeed.

Younes Essouabni

Ranch Hand

Posts: 479

Raghav Sam

Ranch Hand

Posts: 412

posted 15 years ago

Hi,

For shift operators, 'only the five lowest-order bits of the right-hand operand are used as the shift distance, if the left-hand operand is int'.

In case1, the 5 bits are:

In case2, the 5 bits are:

I see that your are new to this forum. Plz do a search for your question before you post. This has been discussed many times before.

System.out.println(32>>32);//case1

the result show : 32

System.out.println(32>>31);//case2

the result show : 0

For shift operators, 'only the five lowest-order bits of the right-hand operand are used as the shift distance, if the left-hand operand is int'.

In case1, the 5 bits are:

**00000**. So, the left-hand operand (32) gets shifted by 0 bits and hence the result is the same: 32.In case2, the 5 bits are:

**11111**. So, the left-hand operand (32) gets shifted by 31 bits and hence the result is: 0.I see that your are new to this forum. Plz do a search for your question before you post. This has been discussed many times before.

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