variable initialisation

[weiliu lili]

public class Test026
{
static Test026 t = new Test026();
String str;
public static void main(String args[]) {
Test026 t = new Test026();
t.method("0");
}
void method(String str) {
str = str;
System.out.println(str);
System.out.println(t.str);
System.out.println(this.str);
}
}
-----------------------------------------------------------------------
The output is:
0
null
null

the explanation:
The str for object t and this remains uninitialised and keep null value
I thought str has already been initialised as "str=str", where m i wrong?
thanks

[Jamal Hasanov]

Hi Weilliu
change
str = str;
to
this.str = str;
str is an object given as a parameter. For accessing class's str you must refer to this
Thanx,
Jamal Hasanov
www.j-think.com

[Karen Leoh]

Hi there..
I hope this helps. When you initialise "str=str", it is done locally. The instance variable is str is still null.
Correct me if I'm wrong.

public class Test026
{
static Test026 t = new Test026();
String str; //this is initialised to null
public static void main(String args[]) {
Test026 t = new Test026();
t.method("0");
}
void method(String str) {
str = str;
System.out.println(str);
System.out.println(t.str); //this called the instance variable str which is null
System.out.println(this.str); //this also call the instance variable str
}
}

[Kaspar Dahlqvist]

Howdy!
Method void method(String s) is currently too ambiguous for the compiler... Right now your method receives a reference to a String called str, and what you do with
str = str;
is to tell Java that you want str to reference the String that str points to. But, hey, it already does...
In your code you create two objects from the class Test026, and each has a instance variable called str. To initialize these to values other than null, you need to use the references to those objects. In other words, in an appropriate place, do the following:
t.str = str;
this.str = str;

Getting the hang of riding, yet?
/Kaspar