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Unexpected output ??

 
Rao Rekha
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Posts: 11
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Could anyone kindly let me know why does the following code prints 3 ?
class TestClass
{
public static void main(String args[])
{
boolean b = false;
int i = 1;
do
{
i++ ;
} while (b = !b);
System.out.println( i );
}
}
Thanks in advance.
 
Gautam Jha
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Because of "(b = !b)" in the "while" statement.
Note its an assignment and not an check. After
the assignment, the value of b is used to determine whether to quit the loop or not? Make sense??
 
Chitra Jay
Ranch Hand
Posts: 76
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do-while loop executes its body atleast once irrespective of whether the condition returns true/false
i gets incremented to 2
goes thru the condition in while
b= !b
in this statement,! has higher precedence than =.
!b evaluates to !false ==> true
now b gets assigned the value true.
(b = (!false)) -> true
since the condition returns true,it enters the loop again,and increments i to 3.
Now,the condition is evaluated once again,
but returns false (because b = (!true) )therefore comes out of the loop and prints 3.
Chitra
 
Rao Rekha
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Posts: 11
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That makes complete sense. Thanks Jha and Chitra.
 
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