>>> operator

[Eugene Lea]

int i = Integer.MIN_VALUE;
byte b = Byte.MIN_VALUE;
i>>>=1;
b>>>=1;
System.out.println(i);
System.out.println(b);
output:
1073741824
-64
Why for i output positive value, for b output negative value ?

[Alfred Kemety]

Integer.MIN_VALUE = 80000000
Byte.MIN_VALUE = 80 = 10000000
when applying the >>> to the byte, it first gets promoted to int then get shifted.
after being shifted because of >>>= it gets implecitly casted back to byte so the value gets truncated.
the output of this code should make you understand what happens.

public class Test {
public static void main(String[] args) {
int i = Integer.MIN_VALUE;
byte b = Byte.MIN_VALUE;
int x = b;
System.out.println(x + ", " + Integer.toBinaryString(x));
i>>>=1;
b>>>=1;
System.out.println(i + ", " + Integer.toBinaryString(i));
System.out.println(b + ", " + Integer.toBinaryString(b) + ", " + Integer.toBinaryString(b).substring(24));
}
}

[ October 14, 2002: Message edited by: Alfred Kemety ]