I can't understand these code!

[Sam Wang]

October 15, 2002
Tech Tips Quiz
[http://developer.java.sun.com/developer/Quizzes/techtips3/index.html]
public class OverDemo1 {
// overload methodA between short/int
static void methodA(short s) {
System.out.println(
"methodA(short) called");
}
static void methodA(int i) {
System.out.println("methodA(int) called");
}
// overload methodB between float/double
static void methodB(float f) {
System.out.println(
"methodB(float) called");
}
static void methodB(double d) {
System.out.println(
"methodB(double) called");
}
public static void main(String args[]) {
// call methodA with char argument
methodA('a'); //methodA(int) called
// call methodB with int argument
methodB(Integer.MAX_VALUE); // methodB(float) called
}
}
Why does methodA('a') call methodA(int i)?
How about char and int and short?
int is 32bit,char and short is 16bit.

[Shishio San]

There was an implicit numeric promotion from char to int that's why the amethod(int i) was called. amethod(short s) can't be called coz you need an explicit cast when converting a char to a short or a short to a char.
P.S one more thing amethod(int i) is the most specific method and that's explain why amethod(float f) wasn't called

[Sam Wang]

Thanks.
Maybe you miss the word 'methodB';
methodB(float f){...}
methodB(double d){...}
methodB(Integer.MAX_VALUE);
//will call methodB(float f) why?

[Shishio San]

because methodB(float f) is more specific than methodB(double d)
I suggest you read This

[Sam Wang]

Thanks again.