Threads

[bobby chaurasia]

To start a thread we use,
Thread t = new Thread( c);
t.start();
This calls the run method of c.
What happens when we do something like:
1) t.run();
( We know that The Thread class implements a generic thread that, by default, does nothing. That is, the implementation of its run method is empty. ) In this case will this method from the Thread class be called ? )
2) t.run();
t.start();

[Shiva Mantri]

1. t.run();
This would execute c.run(), because if you look at implementation of Thread(Runnable c), Thread.run() calls c.run(). Here the Thread is not scheduled. It is executed like anyother method.
2. t.run(); followed by t.start();
This would execute c.run() and then t.start() method registers the thread with the scheduler and will eventually executed by calling t.run().
-Shiva
[ January 12, 2003: Message edited by: Shiva Mantri ]

[Alfred Kemety]

Basicly, if t.run(); is in Thread A, then the method run() MUST return before the next statment in Thread A is executed.
With t.start(); maybe the whole new thread will not start executing - run() method - before all of Thread A finish executing, maybe it will act like when you call t.run(), this is totally at the merci of JVM Thread scheduler.
HTH