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Initialization of Interfaces

 
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Posts: 43
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interface I {
int i = 1, ii = Test.out("ii", 2);
}
interface J extends I {
int j = Test.out("j", 3), jj = Test.out("jj", 4);
}
interface K extends J {
int k = Test.out("k", 5);
}
class Test {
public static void main(String[] args) {
System.out.println(J.i);
System.out.println(K.j);
}
static int out(String s, int i) {
System.out.println(s + "=" + i);
return i;
}
}
Out put produced is
1
j=3
jj=4
3
How does jj=4 and 3 are printed and y not ii=2 printed..
 
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IntelliJ IDE Java
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Please check out the following discussion which handles the same topic:
https://coderanch.com/t/198775/java-programmer-SCJP/certification/Variable-Initialization
 
Chetan M
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Thanks Valentin .. I am clear with the concept now.!
 
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